1 x 144 = 144 2 x 144 = 288 3 x 144 = 432 4 x 144 = 576 5 x 144 = 720 6 x 144 = 864 7 x 144 = 1008 8 x 144 = 1152 9 x 144 = 1296 10 x 144 = 1440 11 x 144 = 1584 12 x 144 = 1728
12 times 5 is 60
5 x 5 = 25 12 x 12 = 144 25 + 144 = 169 13 x 13 = 169 The hypotenuse is 13.
I would do it as follows:305 * 144 = (300*144) + (5*144) = 100*(3*144) + 10*(144/2) [because 5 = 10/2]= 100*(432) + 10*72 = 43200 + 720 = 43920.
Suppose X*(5/4) = 180 Then X = 180*4/5 = 144
1 x 144 = 144 2 x 144 = 288 3 x 144 = 432 4 x 144 = 576 5 x 144 = 720 6 x 144 = 864 7 x 144 = 1008 8 x 144 = 1152 9 x 144 = 1296 10 x 144 = 1440 11 x 144 = 1584 12 x 144 = 1728
The first ten positive integer multiples of 144 are: 1 x 144 = 144 2 x 144 = 288 3 x 144 = 432 4 x 144 = 576 5 x 144 = 720 6 x 144 = 864 7 x 144 = 1008 8 x 144 = 1152 9 x 144 = 1296 10 x 144 = 1440
2 x 2 x 2 x 2 x 3 x 3 = 144 2 x 2 x 3 x 5 x 5 = 300 2 x 2 x 3 = 12, the GCF
12 times 5 is 60
5 x 5 = 25 12 x 12 = 144 25 + 144 = 169 13 x 13 = 169 The hypotenuse is 13.
4 + 5 = 9 x 16 = 144
12 x 12 = 144
I would do it as follows:305 * 144 = (300*144) + (5*144) = 100*(3*144) + 10*(144/2) [because 5 = 10/2]= 100*(432) + 10*72 = 43200 + 720 = 43920.
140 = 2 x 2 x 5 x 7 OR 22 x 5 x 7
The prime factorizations are: 60: 2 X 2 X 3 X 5 120: 2 X 2 X 2 X 3 X 5 144: 2 x 2 x 2 X 2 X 3 X 3
Suppose X*(5/4) = 180 Then X = 180*4/5 = 144
12 x 144 = 1728...........144..........x 12========...........288.......+ 144========..........1728