The product is 1029
The prime factors of 147 are 3 and 7. Specifically, 147 can be expressed as (3^1 \times 7^2) since (147 = 3 \times 7 \times 7).
7 times with a remainder of 7
7
21 goes into 147 seven times.
21 multiplied by 7 is 147.
The prime factors of 147 are 3 and 7. Specifically, 147 can be expressed as (3^1 \times 7^2) since (147 = 3 \times 7 \times 7).
147.
7 times with a remainder of 7
7
21 goes into 147 seven times.
21 multiplied by 7 is 147.
21 times 7= 147 :)
To use the distributive property to solve (10 \times 147), you can break down 147 into two simpler components, such as (100 + 40 + 7). Then, apply the distributive property: [ 10 \times 147 = 10 \times (100 + 40 + 7) = (10 \times 100) + (10 \times 40) + (10 \times 7). ] Calculating each term gives (1000 + 400 + 70 = 1470), so (10 \times 147 = 1470).
10 can go into 147 fourteen times, with a remainder of 7. This is calculated by dividing 147 by 10, which equals 14 with a remainder of 7. The remainder represents the amount left over after dividing as many times as possible by the divisor.
Oh, dude, you're hitting me with some math now? Like, okay, let's break it down. So, 1 times 147 equals 147, and 147 times 1 also equals 147. So, technically, the answer is 1 and 147, but like, you already knew that, right?
~7.095 times or 7 times with a remainder of 14.
3 x 7 x 7 = 147