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assuming 4 16 is meant to be 4/16 then4/16 x 3 = 12/16 = 3/4three quarters
Suppose sqrt(16) = x and cuberoot(16) = y, then then x^2 = 16 = y^3 so that x^(2/3) = y x = y^(3/2).
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The lowest common multiple of 16, 3 and 4 is 48. 16 x 3 = 48, 4 x 12 = 48, and 3 x 16 = 48.
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5.3333
2(4x)=16 8x=16 x=2 24x=16 x=16/24 x=2/3
6x - 2 = 16 : 6x = 16 + 2 = 18 : x = 18÷ 6 = 3 :x - 3 = 3 - 3 = 0 : x - 3 = 0
assuming 4 16 is meant to be 4/16 then4/16 x 3 = 12/16 = 3/4three quarters
NO! 16 x 2 = 32, 16 x 3 = 48
six 3/8 x 16 = (3 x 16)/8 divide both sides by 8 = (3 x 2)/1 = 6/1 = 6 or 8 x 2 = 16 then 3 x 2 = 6
Suppose sqrt(16) = x and cuberoot(16) = y, then then x^2 = 16 = y^3 so that x^(2/3) = y x = y^(3/2).
19
The lowest common multiple of 16, 3 and 4 is 48. 16 x 3 = 48, 4 x 12 = 48, and 3 x 16 = 48.
x + (x - 3) = 16 ? Let's suppose that this is true. 2x - 3 = 16 2x = 19 x = 9.5 Check: 9.5 - ( 9.5 - 3) = 16 ? 9.5 + 6.5 = 16? 16 = 16
16/5 divided by 3/5 = 16/5 x 5/3 = 16/3 = 16 thirds or 5 and 1/3