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What is the degree angle of each side of a octagon?
In total the interior angles add to (8-2)*180 = 6*180 = 1080 degrees. IF the octagon is regular, so that all of its angles are equal, then each one is 1080/8 = 135 degrees.
How many degrees is one angle of a regular octagon?
you have to times 180 degrees by minus 2 of how many sides then divide it by how many side. 8-2=6 6x180=1080 1080divided by 8 = 135 degree is equal to 1 angle of a regular octagon. happy to help
What is the sum of all measures of all the interior angles of a regular octagon?
The sum of the measure of the angles of any polygon is 180 x (the number of sides - 2). So for a triangle it is 180*(3-2) = 180 degrees. So an octagon, 8 sides, is 180 x (8-2) = 180 x 6 = 1080 degrees. This is the same whether all the angles are equal or not.
What are the degrees on octagon corners?
120 It is 135 degrees. ((8 x 180) - 360) / 8 = 135
What is the measure of the vertex angle of an isosceles triangle if one of its base angle measures 8 degrees?
If one base angle is 8°, the other base angle must also be 8°. The total of all angles for a triangle must equal 180°, so 180° - 8° - 8° = 164°.
