2 x 10^19
10 x 19 = 190 9 x 19 = 190 - 19 = 171 2 = 173 - 171 Answer: 9 times with 2 remaining
The number of times 19 can go into 48 is determined by dividing 48 by 19. The quotient is the result of this division. In this case, 48 divided by 19 is equal to 2 with a remainder of 10. Therefore, 19 can go into 48 a total of 2 times with a remainder of 10.
19 zeroes. (One of the 20 zeroes in 1020 is "lost" when multiplying 8.2 by 10 the first time; it becomes 82. This is then multiplied by 10 a further 19 times giving 19 zeroes on the end of "82").
19*14 = 19*(10 + 4) = 19*10 + 19*4 = 190 + 76 = 266 (You could use the distributive property again to split 19 into 10 + 9 but that is multiplying by 19 is simple enough and using the distributive property for that is just laziness.
1 times 19, possibly. or 10 times 1.9 or 1000000*0.000019
1.9 times.
It is: 10/19 times 100 = 52.632% rounded to three decimal places
3 R10
(18 x 9) - (19 x 8) = 10
19 times with 9 of a remainder or 19.9 times.
The charge acquired by the body is (10^{10} \times 1.6 \times 10^{-19} ) Coulombs, where 1.6 x (10^{-19} C) is the charge of an electron. This simplifies to (1.6 \times 10^{-9} C).
2 x 10^19
19 times with a remainder of 10 or 19.2 times
10 x 19 = 190 9 x 19 = 190 - 19 = 171 2 = 173 - 171 Answer: 9 times with 2 remaining
The number of times 19 can go into 48 is determined by dividing 48 by 19. The quotient is the result of this division. In this case, 48 divided by 19 is equal to 2 with a remainder of 10. Therefore, 19 can go into 48 a total of 2 times with a remainder of 10.
shot 19 times and stabed 10 times