17p+17q+p-7q-6p = 12p+17q
19p * 6 = 114p = £1.14. Note: simple calculations like this one are easier to do with a calculator. If you don't have a calculator available, your computer probably has one for you to use (check under "Programs", "Applications", etc).
114P, or 1 pound 14 p
You could do it with 20 quarters or 500 pennies. To combine them, subtract one quarter for each twenty-five pennies. 19q, 25p 18q, 50p 17q, 75p 10q, 250p 3q, 425p 2q, 450p 1q, 475 p
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
17p+17q+p-7q-6p = 12p+17q
Add like terms: 13 - 17 + 2p^2 - 19p - 6p^2 = -4 - 4p^2 - 19p
Well, darling, if you want to find a sum of money that's six times greater than 19p, you simply multiply 19 by 6. That gives you a grand total of £1.14. So, there you have it, honey, a sum of money that's six times greater than 19p is £1.14.
K
The change is 64 p.
19p * 6 = 114p = £1.14. Note: simple calculations like this one are easier to do with a calculator. If you don't have a calculator available, your computer probably has one for you to use (check under "Programs", "Applications", etc).
114P, or 1 pound 14 p
You would change 1 pound to pence, so you would have 100 pence. Divide 100 by 19 to get the answer. In this case it would be 20 stamps with 5p left over.
You could do it with 20 quarters or 500 pennies. To combine them, subtract one quarter for each twenty-five pennies. 19q, 25p 18q, 50p 17q, 75p 10q, 250p 3q, 425p 2q, 450p 1q, 475 p
a,b,c,d are numbers of which atleast one is non zero such that a+b+c+d=0 let p=ab+bc+cd prove that one of 19p+99q and 19q+99p must be negative
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
The answer is 672.