Step 1. Divide by 4v: 4v(3v2 + v - 24) Step 2. 4v(3v - 8)(v + 3)
Yes I can. = v-16-4v = -4v-2 = you have to move all the variables to one side, and all the numbers to the other side... v - 4v + 4v = 16 -2 v= 14
12+ 4v = 25 subract 12 from each side of the '=' sign. 4v = 13 divide each side by 4 v= 3.25 thus: 12+ (4x3.25) = 25
-20v + 4v2 - 5y + vy = 4v2 - 20v + vy - 5y = 4v*(v - 5) + y*(v - 5) = (4v + y)*(v - 5)
It is an equation and the value of v is -8
Solve S = 4v2 for v . -4(4-v)= -2(2v-1) v-16+4v = -2(2v-1) v-16+4v = -4v + 2 -16+5v = -4v + 2 5v = -4v + 18 9v = 18 v = 2
24uv + 35u2 - 30u3 - 28v = 24uv - 28v - 30u3 + 35u2 = 4v*(6u - 7) - 5u2(6u - 7) = (4v - 5u2)*(6u - 7)
Is it 4v-7+8v+4-5 ? If so then you're answer is 12v-8
-8-3v = 4v+48 -3v-4v = 48+8 -7v = 56 v = -8
u^2 + uv + v has no simple factorisation. As a quadratic in u, it can be "factorised" by using the quadratic formula to find the root values (r1 and r2) for u, and then the factorisation would be (u - r1)(u - r2); however the values of the roots are: r1 = (-v + √(v^2 - 4v))/2 r2 = (-v - √(v^2 - 4v))/2 which leads to the complicated "factorisation": u^2 + uv + v = (u + (v + √(v^2 - 4v))/2)(u + (v - √(v^2 - 4v))/2)
It is: -10v+6v = -4v
(4v - 3)(3v - 2), ie v = 3/4 or 2/3
4v-7+8v+4-5 - add the like terms =12v-8 12v and 8 cannot be subtracted because they are not like terms. Like terms have the same variable.
no if 1 plus 1 equals 2 then 2 plus 2 equals 4.
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
One plus one is two. It can be expressed mathematically as 1+1 = 2.
It equals 7