1 x 115, 5 x 23, 23 x 5, 115 x 1 = 115
-8x + 3 = 251 -8x = 251 - 3 -8x = 248 -x = 248 ÷ 8 -x = 31 x = -31
1 x 115, 5 x 23, 23 x 5, 115 x 1
1 x 115 5 x 23
(251 x 7) + 5 = 1762 Answer: 251 with 5 remaining
The first ten positive integer multiples of 115 are as follows: 115 x 1 = 115 115 x 2 = 230 115 x 3 = 345 115 x 4 = 460 115 x 5 = 575 115 x 6 = 690 115 x 7 = 805 115 x 8 = 920 115 x 9 = 1035 115 x 10 = 1150
1 x 115, 5 x 23, 23 x 5, 115 x 1 = 115
1506 = 2 X 753 = 2 X 3 X 251. So 251 is the greatest prime factor of 1506.
1 x 115, 5 x 23, 23 x 5, 115 x 1 = 115
-8x + 3 = 251 -8x = 251 - 3 -8x = 248 -x = 248 ÷ 8 -x = 31 x = -31
1 x 115, 5 x 23, 23 x 5, 115 x 1
The product is 753
1 x 115, 5 x 23 | 23 x 5, 115 x 1
If the number is x then 135*x = 115 so tat x = 115/135 = 0.851851...
% rate= (148/251)x 100% = 58.96%
5 x 115 = 575
251 divided by 365 x 100 = 68.8 percent