16 * 23 = 368
16 times 23 = 368
= (60 / 10) + 2(16 - 23) = 6 + 2(16-23) = 6 + 32 - 46 = -8
Six whole times, and 16/23 of another time.
3 with remainder 16.
8 with remainder 16.
16 x 19 x 23 = 6992
16 times 23 = 368
= (60 / 10) + 2(16 - 23) = 6 + 2(16-23) = 6 + 32 - 46 = -8
Six whole times, and 16/23 of another time.
7 + 16 = 23
3 with remainder 16.
8 with remainder 16.
Not evenly. It goes in 16 times with a remainder of 4.
To find the number of atoms in 16 g of oxygen (O) and 8 g of sulfur (S), we first calculate the number of moles of each element. For oxygen (molar mass ≈ 16 g/mol), 16 g corresponds to 1 mole, which contains (6.022 \times 10^{23}) atoms. For sulfur (molar mass ≈ 32 g/mol), 8 g corresponds to 0.25 moles, which is (0.25 \times 6.022 \times 10^{23} \approx 1.5055 \times 10^{23}) atoms. Thus, the total number of atoms is approximately (6.022 \times 10^{23} + 1.5055 \times 10^{23} \approx 7.5275 \times 10^{23}) atoms.
7
23 goes into 62 a total of 2 times, since 23 multiplied by 2 equals 46, which is less than 62. If you multiply 23 by 3, you get 69, which exceeds 62. Therefore, the answer is 2 times with a remainder of 16.
You can achieve 23 using four fours with the expression: ( (4 \times 4) + (4 / 4) ). Here, ( 4 \times 4 ) equals 16, and ( 4 / 4 ) equals 1. When you add them together, ( 16 + 1 + 6 ) gives you 23.