252 = 2 x 2 x 3 x 3 x 7 or 22 x 32 x 7
As a product of its prime factors: 2*2*3*3*7 = 252
To express 252 as a product of prime factors, we start by dividing it by the smallest prime number, which is 2. This gives us 252 = 2 × 126. Continuing to factor, we find that 126 = 2 × 63, and then 63 = 3 × 21, and finally 21 = 3 × 7. Thus, the complete prime factorization of 252 is (2^2 \times 3^2 \times 7).
2, 3, 7,
252 2x126 2x2x63 2x2x3x3x7
The product of the prime factors of any number is equal to the number itself. Therefore, the product of the prime factors of 350 is 350.
As a product of its prime factors: 2*2*3*3*7 = 252
As a product of its prime factors: 2*2*3*3*7 = 252
252 = 2 x 2 x 3 x 3 x 7
The Prime Factors of 224 are 2, 7The Prime Factors of 252 are 2, 3, 7
252 = 2 * 2 * 3 * 3 * 72, 3 and 7.The prime factors of 252 are: 2, 3, 7
To express 252 as a product of prime factors, we start by dividing it by the smallest prime number, which is 2. This gives us 252 = 2 × 126. Continuing to factor, we find that 126 = 2 × 63, and then 63 = 3 × 21, and finally 21 = 3 × 7. Thus, the complete prime factorization of 252 is (2^2 \times 3^2 \times 7).
2x2x3x3x7 = 252 just multiply 2,2,3,3 and 7 together and this is a product of prime numbers which equals 252 the product just means to multiply
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2, 3, 7,
252 2x126 2x2x63 2x2x3x3x7
It is 504
The LCM of 12, 18, and 21 is 252 Factors of 12: 2^2, 3 Fadtors of 18: 2, 3^2 Factors of 21: 3, 7 Since the LCM of a set of numbers is mathematically defined to be the product of all the prime factors in the set taken to the highest degree they appear, the LCM must be the product of 22 X 32 X 7 = 252. 252 is the smallest number to be divisible by 12, 18, and 21.