All multiples of 27 are divisible by 27, namely:
27, 54, 81, 108, 135, 162, 189, 216, 243, 270, 297, 324, 351, 378, 405, 432, 459, 486, 513, 540, 567, 594, 621, 648, 675, 702, 729, 756, 783, 810, 837, 864, 891, 918, 945, 972, 999, 1026, 1053, 1080, 1107, 1134, 1161, 1188, 1215, 1242, 1269, 1296, 1323, 1350, 1377, 1404, 1431, 1458, 1485, 1512, 1539, 1566, 1593, 1620, 1647, 1674, 1701, 1728, 1755, 1782, 1809, 1836, 1863, 1890, 1917, 1944, 1971, 1998, 2025, 2052, 2079, 2106, 2133, 2160, 2187, 2214, 2241, 2268, 2295, 2322, 2349, 2376, 2403, 2430, 2457, 2484, 2511, 2538, 2565, 2592, 2619, 2646, 2673, 2700, ...
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If you meant what is 27 divisible by, ie what as the factors of 27, then:
The factors of 27 are: 1, 3, 9, 27.
No, because it is divisable by 2. A prime number is only divisable by one and itself.
540 is divisable by... 540, 1, 270, 2, 10, 54, 27, 20... u shold put it in order beter
No, it is not.
no.
No, 6 is divisable by 3 but not divisable by 9, same goes for 12, 15 and 24 ... so on.
Yes because there is 9, 18, 27, ect. including 3 itself.
Not evenly because there will be a remainder of 1
1, 3, 9, 23, 27, 69, 207, 621.
yes 91 is divisable by 7 and 13 so no it isnt a prime #
102,068,001 is NOT a prime number. It is evenly divisable by 3. A prime number is only evenly divisable by 1 and itself. It is also divisable by 9.
No, because it is divisable by 2. A prime number is only divisable by one and itself.
540 is divisable by... 540, 1, 270, 2, 10, 54, 27, 20... u shold put it in order beter
No.
No.
1,3,5
No, it is not.
it cannot be divisable by 5 and 9 but it can be divisable by 2,3,4,6,41,28,and 21