Q: What is 27 s to the third power plus 1?

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3³ + 1³ = 27 + 1 = 28

(x + 1)(x^2 - x + 1)

(-3)(-3) can be written another way to eliminate the negative third power:1/(-33)In this form, all you need to do is divide 1 by the -3 cubed.1/(-33) = 1/(-27) = -0.037037

8 tenths plus 1 third = 9

The sum is 1. 1/3 + 1/3 + 1/3 = 3/3 = 1

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3³ + 1³ = 27 + 1 = 28

a2 + 28a + 27 = 0 (a + 1)(a + 27) = 0 a = -1 or -27 However, the second line is the factorised form, the third is what a is equal to

8 because when something is to the power of 3 it means 2x2x2 and two minuses make a plus :) hope this helps

27. 1 times 2 is just 2. 3 to the third power is 3 times 3 which is 9, times 3, which is 27. If you multiply that by 1 again, it's STILL 27.

y = 3 (y^3)(y^3 - 1) = (3^3)(3^3 - 1) = 27(27 - 1) = 27(26) = 702

(-3)^(-3) = 1/(-3)^3 = 1/-27 = - 1/27

1

(x + 1)(x^2 - x + 1)

(2a + 1)(4a2 - 2a + 1)

1 to the first power, 2 to the second power, 3 to the third power, 4 to the fourth power, 5 to the fifth power...

1 whole, or 1

(-3)(-3) can be written another way to eliminate the negative third power:1/(-33)In this form, all you need to do is divide 1 by the -3 cubed.1/(-33) = 1/(-27) = -0.037037