the answer is 1701 i worked out with a calcutor
To solve the expression (7 \times 9 - 3 \times 9), first calculate (7 \times 9) which equals (63) and (3 \times 9) which equals (27). Subtract these results: (63 - 27 = 36). Thus, the final answer is (36).
(63 ÷ 7) × 3 = 27
27/63 = 3/7
1701LetN = thenumberEquation:N÷ 27 = 63N/27 =63N/27 * 27 = 63 * 27N = 1701
The least common multiple of 27 and 63 is 189.
Twice with a remainder of nine
yes because 9 18 27 36 45 54 63
To solve the expression (7 \times 9 - 3 \times 9), first calculate (7 \times 9) which equals (63) and (3 \times 9) which equals (27). Subtract these results: (63 - 27 = 36). Thus, the final answer is (36).
Well, isn't that a happy little math problem? Let's see here, if we take 1732 and divide it by 63, we find that it goes in about 27 times with a remainder. Remember, there are no mistakes in math, just happy little accidents!
27 × 63 = 1,701
the GCF of 27 and 63 is 9
(63 ÷ 7) × 3 = 27
36+27=63
27:1, 3, 9, 27 63? idk. XD
The factors of 27 are 1, 3, 9, and 27. The factors of 63 are 1, 3, 9, 7, 21, and 63. The common factors of 27 and 63 are 1, 3, and 9.
LCM(27, 63) = 189
27/63 = 3/7