It is: 98.'3'% recurring '3'
Expressed as a percentage, rounded to two decimal places, 259/295 x 100 = 87.80 percent.
0.3 x 295 = 88.5
Do you mean C = (30n+295) over (n-5)? If so then the solution is quite straightforward: C = (30n+295) over n-5 Multiply both sides of the equation by n-5 to eliminate the fraction: C(n-5) = 30n+295 Multiply out the brackets and bring over 295 to the LHS which now will be -295: Cn-5C-295 = 30n Collect like terms by bringing over Cn to the RHS which now will be -Cn: -5C-295 =30n-Cn Factorising 30n-Cn = n(30-C): -5-295 = n(30-C) Divide both sides of the equation by 30-C to make n the subject of the equation: n = (-5C-295) over (30-C) Check that your answer is correct by giving a value to C. For instance if C = 100 then n would = 159/14
percentage == 30%% rate:= 30/100 * 100%= 30%
18 out of 30 as a percentage is 60%.
percentage = 12.88%% rate:= 38/295 * 100%= 0.1288 * 100%= 12.88%
Expressed as a percentage, rounded to two decimal places, 259/295 x 100 = 87.80 percent.
0.3 x 295 = 88.5
percentage of 30% = 30%
Do you mean C = (30n+295) over (n-5)? If so then the solution is quite straightforward: C = (30n+295) over n-5 Multiply both sides of the equation by n-5 to eliminate the fraction: C(n-5) = 30n+295 Multiply out the brackets and bring over 295 to the LHS which now will be -295: Cn-5C-295 = 30n Collect like terms by bringing over Cn to the RHS which now will be -Cn: -5C-295 =30n-Cn Factorising 30n-Cn = n(30-C): -5-295 = n(30-C) Divide both sides of the equation by 30-C to make n the subject of the equation: n = (-5C-295) over (30-C) Check that your answer is correct by giving a value to C. For instance if C = 100 then n would = 159/14
percentage == 30%% rate:= 30/100 * 100%= 30%
18 out of 30 as a percentage is 60%.
25 out of 30 as a percentage is about 83.33%.
12 as a percentage of 30 is 40%.
61.333% is the percentage of 18.4 out of 30.
30/100 asa percentage = 30%=30/100* 100%= 30 * 1%= 30%
the percentage of 0.3 = 30%0.3 * 100% = 30%