3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
4
( x1 + x2) divided by 2 then (y1 +y 2) divided by 2
x ÷ 2x2 = 1/2x
0.5
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
4
112
( x1 + x2) divided by 2 then (y1 +y 2) divided by 2
2
The antiderivative of x/(x2-1) is ln(x2-1)/2. Proof: (ln(x2-1)/2)' = (1/(x2-1))*(x2-1)'/2=1/(x2-1)*(2x/2)=x/(x2-1).
formula for the midpoint of a line
The remainder is 8. (x2 + 4)/(x - 2) = (x + 2) + 8/(x - 2) or x2 + 4 = (x - 2)(x + 2) + 8
X2 (X squared)
x ÷ 2x2 = 1/2x
if x2 = 5 the value of x has to be 5 divided by 2 which is 2.5 x = 2.5
0.5