To write 2 hundreds, 7 tens, and 14 ones in numerical form, you first convert each component into its digit representation. Two hundreds is written as 200, seven tens is 70, and fourteen ones is 14. When you combine these, you add them together: 200 + 70 + 14, which equals 284. Therefore, the final numerical representation is 284.
A. 2 thousands, 14 hundreds, 7 ones B. 3 thousands, 11 hundreds, 47 tens C. 3 thousands, 14 hundreds, 7 ones or..... D. 2 thousands, 11 hundreds, 47 ones
21714.88
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
To find the total, first convert everything to the same unit. Two hundreds is 200, fourteen tens is 140, and three ones is 3. Adding these together: 200 + 140 + 3 equals 343. Therefore, 2 hundreds plus 14 tens plus 3 ones equals 343.
446
To write 2 hundreds, 7 tens, and 14 ones in numerical form, you first convert each component into its digit representation. Two hundreds is written as 200, seven tens is 70, and fourteen ones is 14. When you combine these, you add them together: 200 + 70 + 14, which equals 284. Therefore, the final numerical representation is 284.
254 - has 2 hundreds, 5 tens, and 4 ones
A. 2 thousands, 14 hundreds, 7 ones B. 3 thousands, 11 hundreds, 47 tens C. 3 thousands, 14 hundreds, 7 ones or..... D. 2 thousands, 11 hundreds, 47 ones
To solve this, we first need to convert the hundreds into tens. 2 hundreds is equal to 200, so that is 20 tens. Then, we add the 14 tens to get a total of 34 tens. Finally, we add the 3 ones to get a final total of 342.
21714.88
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
To find the total, first convert everything to the same unit. Two hundreds is 200, fourteen tens is 140, and three ones is 3. Adding these together: 200 + 140 + 3 equals 343. Therefore, 2 hundreds plus 14 tens plus 3 ones equals 343.
what number has 9 hundreds, 2 fewer tens than hundreds, and 2 fewer ones than hundreds
Your correct answer is hundreds place because you have your ones period like ones tens hundreds same with the thousands period ones tens hundreds.
In 5420, you have:5 x thousand; 4 x hundred; 2 x tens; zero x ones (the American ones in math is known as units in British maths!).
one