First subtract 4-2, which equals 2. Then add 2+8=10.
3/10+2/53/10+4/10=7/10
A regular decagon; A 20-gon with 2 lots of 10 congruent sides and angles in an alternating pattern; A 30-gon with 3 lots of 10 congruent sides and angles in an 1-2-3-1-2-3 pattern; A 40-gon with 4 lots of 10 congruent sides and angles in an 1-2-3-4-1-2-3-4 pattern; etc.
2X - 4 = - 10 add 4 to each side 2X - 4 + 4 = - 10 + 4 2X = - 6 divide each side by 2 X = - 3 check in original equation 2(-3) - 4 = - 10 - 6 - 4 = - 10 - 10 = - 10 checks
well if you add together 2 and 2, it makes 4 so ,10 add 10 is 20 ,so double 20, is obviously 40.
If we add -10 and -2 and -4, we get -16.
10.
Divide 4 by 2, then multiply by 3 and then add 4
1 add 4 is 5 and 2 add 3 make 5. 5 add 5 make 10 so 2 x 10 is 20
Yes, in base 10, 2 + 2 is equal to 4. We promise!
Add them together.
The factors of 8 are 1, 2, 4, and 8. The factors that add up to 10 are 2 and 8.
First subtract 4-2, which equals 2. Then add 2+8=10.
1510
The 8 factors of 56 are 1, 2, 4, 7, 8, 14, 28, and 56. 2 and 8 add up to 10. Also, 1, 2, and 7 add up to 10.
(10 + 10)/10 = 20/10 = 2. So you now have used 3 of the tens, just do the same again and you've used six tens and have another 2. Then you can have 2+2 = 4, or 2*2 = 4. Here's another way: (10 + 10 + 10)/10 =3. Then add (10/10) which is 1, to get 4.
2X - 4 = - 10 add 4 to each side 2X - 4 + 4 = - 10 + 4 2X = - 6 divide each side by 2 X = - 3 check in original equation 2(-3) - 4 = - 10 - 6 - 4 = - 10 - 10 = - 10 checks