2 to the power of 2 over 3, or (2^{\frac{2}{3}}), can be expressed as the cube root of (2^2). This simplifies to (\sqrt[3]{4}), which is approximately (1.5874).
(2^5)/2 - (2^(3/2)) = 12
27.22
0.01 is.
8 over 27
8 over the 2 power does not have a clear meaning so it is not possible to answer the question. Please edit the question to include more context or relevant information.
(2^5)/2 - (2^(3/2)) = 12
28,832 to the power of 3/2 equals 4,895,670.204
3 to the power of 1 is 3. 3 to the power of minus 2 is equal to 1 over 3 to the power of 2. 3 to the power of 2 is 9. 3 to the power of 1 times 3 to the power of minus 2 is the same as... 3 divided by 3 to the power of 2. So that gives us 3 divided by 9 which is the same as 1/3.
27.22
45.
0.01 is.
27^(2/3) = [cuberoot(27)]^2 = 3^2 = 9
8 over 27
8 over the 2 power does not have a clear meaning so it is not possible to answer the question. Please edit the question to include more context or relevant information.
(-2/5)3 = - 0.064 -2 / (53) = - 0.016
(1/2)3 = 13/23 = 1/8
To simplify the expression (\frac{3^{-4} \cdot 2^3 \cdot 3^2}{2^4 \cdot 3^n}), first combine the powers of 3 in the numerator: (3^{-4 + 2} = 3^{-2}). The expression becomes (\frac{3^{-2} \cdot 2^3}{2^4 \cdot 3^n}). Next, simplify the powers of 2: (\frac{2^3}{2^4} = 2^{-1}). Thus, the simplified expression is (\frac{2^{-1} \cdot 3^{-2}}{3^n} = \frac{2^{-1}}{3^{n+2}}).