22 + 35 = 2*2 + 3*3*3*3*3 = 4 + 243 = 247
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Two to the fifth power multiplied by three to the second power equals 288.
It is a fifth order polynomial. The two terms cannot be combined, except to factor out x² and get x²(x³ + 1). This can be solved for 5 roots: 0, 0, -1, and two complex roots: 1/2 ± i(√3)/2
(24X5 + 18X3)/6X224/6 and 18/6then,5 -23 - 2-----------for the exponents= 4X3 + 3X========
1
(4x ^2 + 3) + (3x ^2 + 8) = ( 4x^2 + 3x^2 ) + (3+8) = 7x^2 + 11