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6. Let j(x) = x^2 − 2x + 4. Evaluate the following.j(a) =j(3)=j(x^2) =j(x + 3) = j(x + h) =?
A.) j(a) = a^2 - 2a + 4 B.) j(3) = (3)^2 - 2(3) + 4 = 9 - 6 + 4 = 7 C.) j(x^2) = (x^2)^2 - 2(x^2) + 4 = x^4 - 2x^3 + 4 D.) j(x+3) = (x + 3)^2 - 2(x + 3) + 4 = x^2 +6x + 9 - 2x - 6 + 4 = x^2 + 4x + 7 E.) j(x+h) = (x + h)^2 - 2(x + h) + 4 = x^2 + 2hx + h^2 - 2x - 2h + 4
How to make the numbers 2 4 5 6 7 8 9 10 11 12 13 14 15 Only using the numbers 1 2 3 4 once in order of operation please help mee?
1 = (1 + 4) ÷ (2 + 3) 2 = 4 - 3 + 2 - 1 3 = (4 + 3 - 1) ÷ 2 4 = (4 + 3 + 1) ÷ 2 5 = (4 x 2 - 3) x 1 6 = 4 + 3 - 2 + 1 7 = (4 + 3) x (2 - 1) 8 = 4 + 3 + 2 - 1 9 = 4 + 3 + 2 x 1 10 = 4 + 3 + 2 + 1 11 = 4 x 2 + 3 x 1 12 = 4 x 3 x (2 - 1) 13 = 3 x 4 + 2 - 1 14 = 3 x 4 + 2 x 1 15 = 3 x 4 + 2 + 1
What is the LCM of 2 3 4?
12. (6 x 2, 4 x 3 and 3 x 4)
What is 3 equals 2 plus x divided by 4?
Do you mean? 3 = 2 + X/4 multiply through by 4 4/1(3 = 2 + X/4)4/1 12 = 8 + X 4 = X -----------check in original equation 3 = 2 + 4/4 3 = 2 + 1 3 = 3 ----------checks now, if you meant 3 = (2+X)/4 some multiplying through 12 = 2 + X 10 = X you check this one
How X over 2 plus 3 equals 4?
If x/2 +3 = 4 then x = 2
Write three ways to find 3 x 2 x 4?
3 x 2 x 4 = 24 (3 x 2) x 4 = 6 x 4 = 24 3 x (2 x 4) = 3 x 8 = 24 2 x (3 x 4) = 2 x 12 = 24
What are the factors to multiply 144 using more than 2 factors?
2 x 2 x 2 x 2 x 3 x 3 2 x 2 x 2 x 2 x 9 2 x 2 x 3 x 3 x 4 2 x 2 x 36 2 x 4 x 18 2 x 2 x 2 x 3 x 6 2 x 2 x 4 x 9 2 x 8 x 9 2 x 2 x 3 x 12 4 x 4 x 9 4 x 6 x 6 3 x 3 x 16 3 x 4 x 12 2 x 6 x 12 3 x 3 x 4 x 4 2 x 3 x 24
What is two thirds of two thirds of a cup?
2/3 x 2/3 = 4/9.2/3 x 2/3 = 4/9.2/3 x 2/3 = 4/9.2/3 x 2/3 = 4/9.
How do you multiply 144 with more than two factors?
2 x 2 x 2 x 2 x 3 x 3 2 x 8 x 9 2 x 2 x 4 x 9 2 x 2 x 2 x 2 x 9 2 x 2 x 2 x 3 x 6 2 x 3 x 4 x 6 3 x 3 x 4 x 4 3 x 3 x 16
How do you factor x squared plus x minus one half?
(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2
What is 2 x 2 x 3 x 3 x 3 x 3 x 3?
972 4*9*9*3 4*81*3 4*243 =972
What is 2 and 3 4ths x 3?
(2 3/4) x 3 = 11/4 x 3 = 33/4 = 8 1/4
What is the prime factorization of 4 and 243?
2 x 2 =4 3 x 3 x 3 x 3 x 3 = 243
Is your proof about Fermat true or false?
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appy&Peace. Trantancuong.
How do you solve 3 ln x - ln 2 equals 4?
3lnx - ln2=4 lnx^3 - ln2=4 ln(x^3/2)=4 (x^3)/2=e^4 x^3=2e^4 x=[2e^4]^(1/3)
Multiply 2 x 3 x 4?
Question: 2 x 3 x 4 Answer: It's easier to break this down into separate parts. First, multiply 2 x 3 = 6 Then multiply 6 (which is 2 x 3) x 4 = 24 Therefore, 2 x 3 x 4 = 24
What is the solution of x2 plus x plus 1 equals 0?
x2 + x + 1 = 0 ∴ x2 + x + 1/4 = -3/4 ∴ (x + 1/2)2 = -3/4 ∴ x + 1/2 = ± √(-3/4) ∴ x = - 1/2 ± (i√3) / 2 ∴ x = (-1 ± i√3) / 2
