Multiply the diameter by pi, which is approximately 3.14. If 15 cm. is the radius, multiply by 2 x pi.
It is pi x 15 x 15 = pi x 225 = 3.1415 x 225 = 706.84 square cms
You divide circumference / (2 x pi).You divide circumference / (2 x pi).You divide circumference / (2 x pi).You divide circumference / (2 x pi).
circumference = 2 x π x radius = 2 x 3.14 x 15 cm = 94.2 cm
2 x pi x 2 = 4 x pi
47.1 feet Circumference = 2 x pi x r OR pi x d 3.14 x 15 feet = 47.1 feet
The formular for the surface area of a cylinder is 2(pi)rh + 2(pi)r2 where r=radius and h=height and pi=3.14 SA= 2 x 3.14 x 15 x 30 + 2 x 3.14 x 152 =4239
Multiply the diameter by pi, which is approximately 3.14. If 15 cm. is the radius, multiply by 2 x pi.
It is pi x 15 x 15 = pi x 225 = 3.1415 x 225 = 706.84 square cms
You divide circumference / (2 x pi).You divide circumference / (2 x pi).You divide circumference / (2 x pi).You divide circumference / (2 x pi).
If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.
circumference = 2 x π x radius = 2 x 3.14 x 15 cm = 94.2 cm
2 x pi x 2 = 4 x pi
pi * 225/4 Radius is 15/2 pi r2 = pi * (15/2)2 = pi * 225/4
Circumference = (2) x (pi) x (Radius)= (2 pi) times (X + 4)= same as (2 pi X) + (8 pi)= same as [ pi (2X + 8) ]
Radius = 15Diameter = 2 x radius = 30Circumference = pi D = 30 pi = 94.25 (rounded)
sin x - cos x = 0sin x = cos x(sin x)^2 = (cos x)^2(sin x)^2 = 1 - (sin x)^22(sin x)^2 = 1(sin x)^2 = 1/2sin x = ± √(1/2)sin x = ± (1/√2)sin x = ± (1/√2)(√2/√2)sin x = ± √2/2x = ± pi/4 (± 45 degrees)Any multiple of 2pi can be added to these values and sine (also cosine) is still ± √2/2. Thus all solutions of sin x - cos x = 0 or sin x = cos x are given byx = ± pi/4 ± 2npi, where n is any integer.By choosing any two integers , such as n = 0, n = 1, n = 2 we can find some solutions of sin x - cos x = 0.n = 0, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(0)(pi) = ± pi/4 ± 0 = ± pi/4n = 1, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(1)(pi) = ± pi/4 ± 2pi = ± 9pi/4n = 2, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(2)(pi) = ± pi/4 ± 4pi = ± 17pi/4