answersLogoWhite

0


Best Answer

It can't be simplified any further so it is:

2m + 2n + p

User Avatar

Wiki User

βˆ™ 8y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is 2m plus 2n plus p?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How do you solve L equals 2M plus 2N for N?

N=l-m


2m - n - m - 2n?

0


If two odd numbers are added together what is the result?

Two odd numbers added together will always be an even number. I'll show how: Let M and N be any two integers. 2M is even, and 2N is even. So (2M +1) is an odd number, and (2N + 1) is an odd number. (2M +1) + (2N +1) = 2M + 1 + 2N +1 = 2M + 2N + 2 = 2(M + N + 1), which is even.


What are the factor of 2mp2 - 24mpq plus 72mq2?

2m(p - 6q)(p - 6q)


How do I simplify simplify 5 plus n-p plus 2n-4?

is eassy


Is 2m-2n equals 0 linear?

Yes.


Find the sum of the given polynomials 5m plus 2n comma n minus 3m comma and 7 minus 3n What is the answer?

5m+2n, n-3m, 7-3n (5m+2n)+(n-3m)+(7-3n)=2m+7


How do you simplify 5n plus 2n and can you explain because i was sick but my friend gave me the homwork?

5n+2n=7n If the variable is the same, n, then you can add the coefficients, 5 and 2. In General an+bn=(a+b)n FOR A CASE THAT DOES NOT WORK. 5n+2m=5n+2m You cannot combine unlike variables


What is 2n plus 4m -2n plus m?

2n + 4m - 2n + m = 5m


Is the sum of an even whole number and an odd whole number always odd?

Yes --------------------------------------------- Let n be an integer. Then 2n is an even number Let m be an integer. Then 2m is an even number and 2m + 1 is an odd number. Then: even + odd = (2n) + (2m + 1) = (2n + 2m) + 1 = 2(n + m) + 1 = 2k + 1 (where k = m + n) which is an odd number.


How do you prove by algebra that if you add two even numbers you get an even number?

You use the definition of even numbers which says it is a number of the form 2n for some integer n, and you take two of them, say 2n and 2m and add them and see that you have 2n+2m=2(n+m) and since n and m are integers so is n+m so lets call it p so the sum is 2p and this is even by definition of even numbers


How do you know that adding an even number to an even number results in an even number?

This is a simple proof of what you ask. Any even number can be thought of as 2n for some integer n. So let's take two even numbers 2n and 2m and add them. 2n+2m=2(n+m) and since n and m are integers so is n+m, call it p, then the sum is 2p and that is even since it is a multiple of 2.