If you mean: 2x2 -9x +4 then it can be factored to (2x-1)(x-4)
2x2 - 9x + 4 = (2x - 1)(x - 4)
2x2-9x+4 = (2x-1)(x-4) when factored
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
2x2 + 10 - 9x = 0 or 2x2 - 9x + 10 = 0 So (x - 2)*(2x - 5) = 0
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
2x2 - 9x + 4 = (2x - 1)(x - 4)
2x2-9x+4 = (2x-1)(x-4) when factored
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
(2x + 1)(x + 4)
2x2 + 10 - 9x = 0 or 2x2 - 9x + 10 = 0 So (x - 2)*(2x - 5) = 0
2x2 - 9x = 18 2x2 - 9x -18 = 0 (2x - 18)(x + 9) x= -9 and 9
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
If: 2x2-9x-5 = 0 Then: (2x+1)(x-5) = 0 Therefore:: x = -1/2 or x = 5
(2x + 1)(x + 4) or (2x - 1)(x - 4) depending on the sign of the term in x and 4 being positive.
2x2 - 9x + 10 = 2x2 - 4x - 5x + 10 = 2x(x - 2) - 5(x - 2) = (x - 2)(2x - 5)
Factors are (2x + 1)(x + 4), making x either -0.5 or -0.25
2x2 - 9x + 4 you do 4 muliply to 2 to get the factors ok which can be multiplied to give 8 and add/subtract to give -9x. OK!!!!! Factors of 8 are: 2 X 4 but it doesnt add upto give 9 so -8 and -1 give -9 when added ok!!!! 2x2 -8x -1x + 4 take common factors 2x(x - 4) - 1(x - 4) (x-4) is common so take one out and other from ooutside brackets Answer 2x2 - 9x + 4 you do 4 muliply to 2 to get the factors ok which can be multiplied to give 8 and add/subtract to give -9x. OK!!!!! Factors of 8 are: 2 X 4 but it doesnt add upto give 9 so -8 and -1 give -9 when added ok!!!! 2x2 -8x -1x + 4 take common factors 2x(x - 4) - 1(x - 4) (x-4) is common so take one out and other from ooutside brackets Answer is (2x-1) (x-4) Hope i helped!!!!!!!