2 x 2 + 8 - 6 = 6
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
2x2+13x+15 = (2x+3)(x+5)
2x2 + 15x + 25 = (2x + 5)(x + 5)
2x2 + 11x + 15 = (x + 3)(2x + 5).
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2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
2x2 equals 5
2x2+13x+15 = (2x+3)(x+5)
y = 2x^(2) + 3x + 7 dy/dx = 2(2)x^(2-1) + 3(1)x^(1-1) + 7(0)x^(0-1) dy/dx 4x^(1) + 3x^(0) + 0 dy/dx = 4x + 3(1) dy/dx = 4x + 3 The answer!!!!! I have made a bit of 'heavy weather' of this but only to try and show you how it works out.
2x2 + 3x + 1 = (x + 1)(2x + 1)
8 - 2x2 = x + 22 - 7Combine like terms on the right side:8 - 2x2 = x + 15Subtract 8 from each side:-2x2 = x + 7Add 2x2 to each side:0 = 2x2 + x + 7
2x2 + 15x + 25 = (2x + 5)(x + 5)
2x2 + 11x + 15 = (x + 3)(2x + 5).
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6
4x2-x+2x2 is 6x2-x when simplified