(2X/3) = 1
multiply through by 3
3[(2X/3) = 1]
2X = 3
divide both sides integers by 2
(2/2)X = 3/2
X = 3/2
========check in original equation
2(3/2)/3 = 1
(6/2)/3 = 1 ( or just cancel 2 in numerator and denominator )
3/3 = 1
1 = 1
=====checks
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y= 1/2x - 2/3
2x-1=-32x=-3+1x=-2/2x=-1
2x + 3y = 1 y = 1/3 - 2x/3
2x - 3 - 8 = 1. 2x - 11 = 1. 2x = 12.x = 6!
the answer is - 2...