(2X/3) = 1
multiply through by 3
3[(2X/3) = 1]
2X = 3
divide both sides integers by 2
(2/2)X = 3/2
X = 3/2
========check in original equation
2(3/2)/3 = 1
(6/2)/3 = 1 ( or just cancel 2 in numerator and denominator )
3/3 = 1
1 = 1
=====checks
y= 1/2x - 2/3
2x-1=-32x=-3+1x=-2/2x=-1
2x + 3y = 1 y = 1/3 - 2x/3
2x - 3 - 8 = 1. 2x - 11 = 1. 2x = 12.x = 6!
the answer is - 2...
y= 1/2x - 2/3
2x-1=-32x=-3+1x=-2/2x=-1
2x + 3y = 1 y = 1/3 - 2x/3
2x - 3 - 8 = 1. 2x - 11 = 1. 2x = 12.x = 6!
x = 1 ------------- 3 = 2x + 1 -1 -1 2=2x /2 /2 1=x
y-2x=3 -y -y -2x=3-y -3 -3 -2x-3=-y /-1 /-1 2x+3=y y=2x and y=2x+3 have the same slope of 2, so they are parallel. Hope this helps! ;D
4x2 - 2x - 3 = 0 (2x + 1)(2x - 3) = 0 x = -(1/2) or (3/2)
the answer is - 2...
2x +1 = 5x-2 2x +3= 5x 3 = 3x x=1
x= (-1/2)y-2.5
2x + 2/3= 5/3 2x= 3/3 2x=1 x=1/2
(1, -1)