-2x+5=13 you subtract 5 away from +5 and this cancels out. you then do the same to the other side by taking 5 away from 13 therefor you get 8. Now you have -2x=8, take -2x and divide it into 8 and you get 4.
2x + 5 = 31 2x = 31 - 5 = 26 x = 13
= 18x + 13
5+2x+8 To solve for x, we can first set this expression equal to 0. Doing this makes the expression a solvable equation. 5+2x+8=0 Add 5 and 8. 13+2x=0 Then, subtract 13 so that the x is on one side of the equation. 2x=-13 Dive both sides of the equation by 2 to get x by itself. 2x/2=-13/2 That gives us... x=-13/2 You can use long division to divide this fraction out if a decimal answer is needed.
4x - 3 = 2x + 54x - 2x = 5 + 32x = 8x = 8/2x = 4To check:4(4) - 3 = 132(4) + 5 = 13
3x+5 = 2x+13 3x-2x = 13-5 x = 8
2x + 5 = 13 2x = 8 2x/2 = 8/2 x=4
4+2x-2x+1=13+6 Combine like terms. (4+1=5; 2x-2x=0; 13+6=19) 5=19 This problem has no solution.
-2x+5=13 you subtract 5 away from +5 and this cancels out. you then do the same to the other side by taking 5 away from 13 therefor you get 8. Now you have -2x=8, take -2x and divide it into 8 and you get 4.
2x + 5 = 31 2x = 31 - 5 = 26 x = 13
= 18x + 13
13 + 2x = 32x = 3 - 132x = -10x = -5
There is no solution to: 4(2x + 2) + 12 > 1004(2x + 2) + 12 > 100 For 4(2x + 2) + 12 > 1004(2x + 2) + 12 to have a solution x < -1 which makes 1004(2x + 2) + 12 < 12, BUT 1004(2x + 2) + 12 is supposed to be greater than 100. Perhaps there is a missing operator in the digits of 1004?
2x + y = 5 so y = 5 - 2x; This gives x - 3(5 - 2x) = 13 ie x + 6x = 13 + 15 so x = 4 and y must be -3
5 + 2x ≥ 13 Subtract 5 from both sides: 2x ≥ 8 Divide both sides by 2: x ≥ 4
6 + 2x + 5 = 11 + 2x
5+2x+8 To solve for x, we can first set this expression equal to 0. Doing this makes the expression a solvable equation. 5+2x+8=0 Add 5 and 8. 13+2x=0 Then, subtract 13 so that the x is on one side of the equation. 2x=-13 Dive both sides of the equation by 2 to get x by itself. 2x/2=-13/2 That gives us... x=-13/2 You can use long division to divide this fraction out if a decimal answer is needed.