64-x2 = (8-x)(8+x) when factored
(4+x) (2x-3)
x(4x-2)
x2 - 2x = x(x - 2)
(2x - 1)(x + 3)
64-x2 = (8-x)(8+x) when factored
(4+x) (2x-3)
x(4x-2)
x2 - 2x = x(x - 2)
(2x - 1)(x + 3)
x2 + 7x - 56 cannot be factorised.
You can use the formula for factoring the difference of two squares in this case.
Factor out a 22(X2 + X - 12)2(X - 3)(X + 4)===========
The correct factorization of 5 x plus 2 -3x x plus 2 is 2x+4.
6(2x - 3y)
6(u-14)
(1-y)(1+y)