2(x-32)(x+60)
64-x2 = (8-x)(8+x) when factored
(4+x) (2x-3)
x(4x-2)
x2 - 2x = x(x - 2)
(2x - 1)(x + 3)
64-x2 = (8-x)(8+x) when factored
(4+x) (2x-3)
x(4x-2)
x2 - 2x = x(x - 2)
(2x - 1)(x + 3)
x2 + 7x - 56 cannot be factorised.
You can use the formula for factoring the difference of two squares in this case.
The expression ( n^2 - 3n - 4 ) can be factored by finding two numbers that multiply to (-4) (the constant term) and add to (-3) (the coefficient of the linear term). These numbers are (-4) and (1). Thus, the factored form is ( (n - 4)(n + 1) ).
Factor out a 22(X2 + X - 12)2(X - 3)(X + 4)===========
The correct factorization of 5 x plus 2 -3x x plus 2 is 2x+4.
6(2x - 3y)
6(u-14)