480
The answer is 40, 2^3=8 2^5=32, so 32+8=40
3 times with a remainder of 5
12/3 * 21/5 = 5/3 * 11/5 = 11/3 = 32/3
It is: (10 and 2/3) times 3 = 32
The smallest number that can be divided exactly by 24, 32, and 40 is their least common multiple (LCM). To find the LCM, we first determine the prime factorization of each number: (24 = 2^3 \times 3), (32 = 2^5), and (40 = 2^3 \times 5). The LCM takes the highest power of each prime: (2^5), (3^1), and (5^1). Thus, the LCM is (2^5 \times 3^1 \times 5^1 = 480). Therefore, the smallest number that can be divided exactly by 24, 32, and 40 is 480.
32 - (15 x 2) + 3 = 5
Prime factors of 90 are 2 x 3 x 3 x 5, or 2 x 32 x 5.
The answer is 40, 2^3=8 2^5=32, so 32+8=40
Nothing times 5=32
32 times 5 equals 160
Applying BODMAS, 32 - (15 x 2) + 3 = 5
It is 5 times 6.4 = 32
23 * 32 * 5 = 8 * 9 * 5 = 360
3 times with a remainder of 5
12/3 * 21/5 = 5/3 * 11/5 = 11/3 = 32/3
It is: (10 and 2/3) times 3 = 32
The smallest number that can be divided exactly by 24, 32, and 40 is their least common multiple (LCM). To find the LCM, we first determine the prime factorization of each number: (24 = 2^3 \times 3), (32 = 2^5), and (40 = 2^3 \times 5). The LCM takes the highest power of each prime: (2^5), (3^1), and (5^1). Thus, the LCM is (2^5 \times 3^1 \times 5^1 = 480). Therefore, the smallest number that can be divided exactly by 24, 32, and 40 is 480.