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Let the numbers by 'm' & 'n' Hence m + n = 12 mn = 35 Hence m = 35/n Substitute 35/n + n = 12 Multiply through by 'n' 35 + n^2 = 12n n^2 - 12n + 35 = 0 It is now in Quadratic Form ; Factor ( n - 7)(n - 5) = 0 Hence n= 7 or n= 5 It follows that m = 5 , or m = 7
It is any one of infinitely many fractions of the form (5*n)/(35*n) where n is a no-zero integer or where 1/n is a common factor of 5 and 35.
To sum numbers 1 through N, use this formula: (1 + N)*N/2, so (1+35)*35/2 = 630.
n*35 or 35n
It is 35*n or 35n.