11/15
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β 13y agoExpressed as a proper fraction in its simplest form, by dividing the numerator and denominator by 11, 33/55 is equal to 3/5 or three fifths. 33/55 = (3×11)/(5×11) = 3/5
11/9 x 3/5 = 33/45 = 11/15
5 wholes and 3 over 11 as a decimal = 5.27275 3/11= 5 + (3 ÷ 11)= 5 + 0.2727= 5.2727
18 9 3 ---- divide by 2= ----- divide by 3= ----- 30 15 5 so your answer is 3 over 5
4/9 ÷ 11/5 = 4/9 x 5/11 = 4x5/9x11 = 20/99
Expressed as a proper fraction in its simplest form, by dividing the numerator and denominator by 11, 33/55 is equal to 3/5 or three fifths. 33/55 = (3×11)/(5×11) = 3/5
divide both numbers by their common factor (5). 15 divide by 5 is 3 25 divide by 5 is 5 So...... 3 over 5
11/9 x 3/5 = 33/45 = 11/15
5 wholes and 3 over 11 as a decimal = 5.27275 3/11= 5 + (3 ÷ 11)= 5 + 0.2727= 5.2727
18 9 3 ---- divide by 2= ----- divide by 3= ----- 30 15 5 so your answer is 3 over 5
4/9 ÷ 11/5 = 4/9 x 5/11 = 4x5/9x11 = 20/99
There are infinitely many such numbers. 958 is one such.
3, 5, 11
11 over 3
prime numbers that divide into 1155 = 3, 5, 7, 11
(5/11) / (3/7) = (5/11) * (7/3) = (5*7) / (11*3) = 35 / 33
4/5 ÷ 3/5 = 4/3 or 11/3