3root(6)+5root(2)
you really answered it yourself!
6 radical 2
2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7
36
2 + 5 + 3 + 3 = 13
4√5 + 4√5 = 8√5.
2 radical 30
-2 √5 + 3 √5 = (-2 + 3) √5 = 1 √5 = √5
1rad5 + 2rad5 = 3rad5 3 radical 5
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
2 radical 2
2 times radical 5 or about 4.472135955
6 radical 2
2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7
76
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
36
2 3/5 = 13/5 as a radical: √132/52 = √169/25 because √169/25 = √169/√25 = 13/5 = 2 3/5