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The cubed root of 2, or 21/3, is equal to 1.259921
The square root of 2, or 21/2, is equal to 1.414214
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What is 3 times 3 square root 2?
3(3 square root of 2) = 9(square root of 2)
What is the square root of 3 divided by 2 plus the square root of 3 divided by 2?
2 times the Square root of 3 + 4
Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
What is the cube root of 2 an 3?
The cube root of 2 is 1.2599210498948732 (rounded).The cube root of 3 is 1.4422495703074083 (rounded).
What is the square root of 2 3 and 4?
1.4142135 is the square root of 2 1.7320508 is the square root of 3 2.0000000 is the square root of 4
What is 3 root 2 minus root 2?
2 root 2
What is 3 root 2 plus 2 root 2?
5 root 2
Simplify the square root of 8 multiplied by the square root of 18?
root 8 = root 4 x root 2 = 2 root 2, root 18 = root 9 x root 2 = 3 root 2; 2 root 2 x 3 root 2 = 6 x 2 = 12
Square root 2 times square root 3 times square root 8?
square root 2 times square root 3 times square root 8
2 - root 3 by root 3?
-1
What is root 3 times 2 root 3 simplified?
√3 x 2√3 = 2 (√3)2 = 2 x 3 = 6
What is the square root of 3 divided by 2 plus the square root of 3 divided by 2?
2 times the Square root of 3 + 4
What is Square root of 3 plus square root of 3?
sqrt(3) + sqrt(3) = 2*sqrt(3) NOT sqrt(3 + 2)
What is sin cos tan csc sec cot of 30 45 60 degrees?
Sin(30) = 1/2 Sin(45) = root(2)/2 Sin(60) = root(3)/2 Cos(30) = root(3)/2 Cos(45) = root(2)/2 Cos(60) = 1/2 Tan(30) = root(3)/3 Tan(45) = 1 Tan(60) = root(3) Csc(30) = 2 Csc(45) = root(2) Csc(60) = 2root(3)/3 Sec(30) = 2root(3)/3 Sec(45) = root(2) Sec(60) = 2 Cot(30) = root(3) Cot(45) = 1 Cot(60) = root(3)/3
Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
Can 2 divided by 2 square root 3 be simplified?
Yes. Multiply both the bottom and top by root 3. Then you have 2 root 3 over two. 2 over 2 simplifies to 1, so the final answer is the square root of 3.
Find the two numbers whose product is 1 and whose sum is 1?
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
