This is a simultaneous equation question.
Arrange both equations in line with their letters and numbers and then simplify them:
(3x-3y = 12) divide all terms by 3
(-8x+4y = -16) divide all terms by 4
This will give you:
x - y = 4
-2x+y = -4
Adding both equations together will give you:
-x = 0
So x = 0, substitute this value for x in the original equations to find the value of y:
x = 0 and y = -4
Note that -3*-4 = 12 and that +4*-4 = -16
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(N/8)=(12/16) N= (12*8/16) N=6
12 divided by 3 equals 4. Then, 4 times 3 equals 12. Finally, 4 plus 12 equals 16.
It does not.
12 = r/3 + 16