5(3x^2 - 7)
3x = 35 ??? 3x = 35 x = 35/3 ------------- ( about 11 and 7/10 )
2x+3x=35 5x=35 x=7
It is an equation and the value of x is 32/3
If you mean 2x2 + 3x = (3x - 1)2 - x2 Then you can solve it this way: Expand: 2x2 + 3x = 9x2 - 6x + 1 - x2 Group like terms: 2x2 + 3x = 8x2 - 6x + 1 6x2 - 9x - 1 = 0 Complete the square: 6x2 - 9x = 1 x2 - 3x/2 = 1/6 x2 - 3x/2 + 9/16 = 1/6 + 9/16 (x - 3/4)2 = 8/48 + 27/48 (x - 3/4)2 = 35/48 Solve for x: x - 3/4 = ± √(35/48) x - 3/4 = ± √(35/3) / 4 x = 3/4 ± √(35/3) / 4 x = [3 ± √(35/3)] / 4 If you mean something else, then you'll need to be clearer with your question.
5(3x^2 - 7)
3x = 35 ??? 3x = 35 x = 35/3 ------------- ( about 11 and 7/10 )
2x+3x=35 5x=35 x=7
By subtracting 2x from 3x and getting x, which is equal to 35.
7x5=3x-9 35=3x-9 35+9=3x 44=3x 44/3=x 14.3=x x=14.3
It is an equation and the value of x is 32/3
If you mean 2x2 + 3x = (3x - 1)2 - x2 Then you can solve it this way: Expand: 2x2 + 3x = 9x2 - 6x + 1 - x2 Group like terms: 2x2 + 3x = 8x2 - 6x + 1 6x2 - 9x - 1 = 0 Complete the square: 6x2 - 9x = 1 x2 - 3x/2 = 1/6 x2 - 3x/2 + 9/16 = 1/6 + 9/16 (x - 3/4)2 = 8/48 + 27/48 (x - 3/4)2 = 35/48 Solve for x: x - 3/4 = ± √(35/48) x - 3/4 = ± √(35/3) / 4 x = 3/4 ± √(35/3) / 4 x = [3 ± √(35/3)] / 4 If you mean something else, then you'll need to be clearer with your question.
x + (x+1) + (x+2) = 108 3x + 3 = 108 3x = 105 x = 35 35,36,37
3x - 35
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
2p
If: 4x+3x = 35Then: 7x = 35So: x = 35/7 => x = 5