(1, 1)
(-1, 5)
4x plus 7 plus 3x equals 19 plus xx = 2
(2, 7)
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
(1, 1)
3x + 4= 7 3x= 7-4 3x/3 = 3/3 x=1
(5, 1)
(-1, 5)
(-1, 5)
3x2 + 22x + 7 = 3x2 +21x + x + 7 = 3x(x + 7) + (x + 7) = (x + 7)(3x + 1)
x = 1/3
4x plus 7 plus 3x equals 19 plus xx = 2
(2, 7)
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
3x + 2 + 2x = 7; 3x + 2x = 5x, so 5x + 2 = 7; 7-2=5, so 5x=5. 5x divided by 5 and 5 divided by 5 equals 1, so x equals 1.
3x+7=4x 7=4x-3x 7=x