(1, 1)
(-1, 5)
4x plus 7 plus 3x equals 19 plus xx = 2
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
(1, 1)
3x + 4= 7 3x= 7-4 3x/3 = 3/3 x=1
(-1, 5)
(-1, 5)
-2x + 3y = -7 3x + y = 16 simultaneous equations. Elimination a letter. Arbitrarily select 'y' Hence multiply the bottom eq'n by ' -3' Hence -2x + 3y = -7 -9x - 3y = -48 Add the eq'ns/ -11x = =55 x = -55/-11 = 5 When x = 5 , substitute into either eq'n for 'y' -2(5) + 3y = -7 -10 + 3y = -7 3y = 3 y = 1 Hence answer in ( x,y) fpr, is ( 5,1).
3x2 + 22x + 7 = 3x2 +21x + x + 7 = 3x(x + 7) + (x + 7) = (x + 7)(3x + 1)
x = 1/3
4x plus 7 plus 3x equals 19 plus xx = 2
3x + 2 + 2x = 7; 3x + 2x = 5x, so 5x + 2 = 7; 7-2=5, so 5x=5. 5x divided by 5 and 5 divided by 5 equals 1, so x equals 1.
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
3x+7=4x 7=4x-3x 7=x