9y-3y=6y; 6y+2y=8y; so your answer is 8y
9y - 18 = 3y subtract 3y from both sides 6y - 18 = 0 add 18 to both sides 6y = 18 divide by 6 on both sides y = 3
13x - 9y - 10
3x-3y=-9 and 9x-9y=-27 both simplifies to x-y=-3.
2x - 3y = 5 => 3y = 2x - 5 has a gradient of 2/3 9y + bx = 4 => 9y = -bx + 4 has a gradient of -b/9 The two gradiends must be the same if the two lines are parallel: 2/3 = -b/9 so that b = -6
9y-3y=6y; 6y+2y=8y; so your answer is 8y
12y+3=9y-15 3y=-18 y=-6
10y= 6y+5+3y 10y=6+9y y=6
9y - 18 = 3y subtract 3y from both sides 6y - 18 = 0 add 18 to both sides 6y = 18 divide by 6 on both sides y = 3
13x - 9y - 10
3x-3y=-9 and 9x-9y=-27 both simplifies to x-y=-3.
To simplify the expression 2x + 3y + 4x + 9y, you first combine like terms. Adding the coefficients of x terms gives 2x + 4x = 6x. Similarly, adding the coefficients of y terms gives 3y + 9y = 12y. Therefore, the simplified expression is 6x + 12y.
2x - 3y = 5 => 3y = 2x - 5 has a gradient of 2/3 9y + bx = 4 => 9y = -bx + 4 has a gradient of -b/9 The two gradiends must be the same if the two lines are parallel: 2/3 = -b/9 so that b = -6
there are several methods .... elimination, substition, graphing, and cramer's rule for substitution : (1st eq) 6x - 3y = 9 (2nd eq) 9y = -3x + 2x simplifies into 9y = -x or x = -9y substitute this into the (1st eq) 6(-9y) - 3y = 9 -54y - 3y = 9 -57y = 9 y = -9/57 =-3/19 now use this to find the x value ... x = -9y = -9(-3/19) x = 27/19 thus the answer is the ordered pair (27/19, -3/19)
3(3y + 2) + 8y 9y + 6 + 8y 17y + 6
Add 3y to each side: 12y = 24 Divide each side by 12: y = 2.
12x - 9y = 6, 12x + 20y = 64 29y = 58 y = 2 x = 2