28/45 x 100 = 62.2 %
5 x 5 = 25 2 x 2 x 7 = 28 3 x 3 x 5 = 45
The LCM of 45, 28, and 150 is 6,300, which is the multiple of the highest power of prime factors from all of the given numbers (22 x 32 x 52 x 7 = 2 x 2 x 3 x 3 x 5 x 5 x 7 = 6300). (Prime factors: 45 = 32 x 5; 28 = 22 x 7; 150 = 2 x 3 x 52)
(2 x 9) + (3 x 9) = 5 x 9 = 45
28/5 x 7/9 = 196/45 = 4 and 16/45
4/5 = 0.80 ...0.80 x 35 = 28
45 - 28 = 17.
1 x 45 = 45 2 x 45 = 90 3 x 45 = 135 4 x 45 = 180 5 x 45 = 225 6 x 45 = 270 7 x 45 = 315 8 x 45 = 360 9 x 45 = 405 10 x 45 = 450 11 x 45 = 495 12 x 45 = 540
The first ten positive integer multiples of 45 are as follows: 1 x 45 = 45 2 x 45 = 90 3 x 45 = 135 4 x 45 = 180 5 x 45 = 225 6 x 45 = 270 7 x 45 = 315 8 x 45 = 360 9 x 45 = 405 10 x 45 = 450
You should use your calculator for such simple sums. It is far quicker and involves fewer key depressions. I could tell you that the answer is 12.6 but how can you be sure that I did not make a mistake? Or that I am not messing about?
1 x 28 = 282 x 28 = 563 x 28 = 844 x 28 = 1125 x 28 = 1406 x 28 = 1687 x 28 = 1968 x 28 = 2249 x 28 = 25210 x 28 = 280
454 = 45 x 45 x 45 x 45 = 4 100 625