No. 499 is not evenly divisible by nine.
Here's a mathematical trick. Any number wholly divisible by 3 has the sum of its digits equal to 3 or a multiple of 3. 199 : 1 + 9 + 9 = 19....NOT divisible by 3 209 : 2 + 0 + 9 = 11....NOT divisible by 3 390 : 3 + 9 + 0 = 12....YES, this is divisible by 3 499 : 4 + 9 + 9 = 22....NOT divisible by 3 Note : 390 ÷ 3 = 130
499-199 is equal to 300.
499 take away 199; 499-100=399 then; 399-99=300
It means "499 common era", i.e. the year 499 past 0. It's another way of saying "AD 499".
499 + 1 = 500
199 - 499 = -300
499 is a whole number.
499 times 10 is 4,990
There are 300 three digit numbers that are divisible by neither 2 nor 3. There are 999 - 100 + 1 = 900 three digit numbers. 100 ÷ 2 = 50 → first three digit number divisible by 2 is 50 × 2 =100 999 ÷ 2 = 499 r 1 → last three digit number divisible by 2 is 499 × 2 = 998 → there are 499 - 50 + 1 = 450 three digit numbers divisible by 2. 100 ÷ 3 = 33 r 1 → first three digit number divisible by 3 is 34 × 3 = 102 999 ÷ 3 = 333 → last three digit number divisible by 3 is 333 × 3 = 999 → there are 333 - 34 + 1 = 300 three digit numbers divisible by 3. The lowest common multiple of 2 and 3 is 6, so these have been counted in both those divisible by 2 and those divisible by 3. 100 ÷ 6 = 16 r 4 → first three digit number divisible by 6 is 17 × 6 = 102 999 ÷ 6 = 166 r 3 → last three digit number divisible by 6 is 166 × 6 = 996 → there are 166 - 17 + 1 = 150 → there are 450 + 300 - 150 = 600 three digit numbers that are divisible by either 2 or 3 (or both). → there are 900 - 600 = 300 three digit numbers that are divisible by neither 2 nor 3.
$499 (USD)/€499/£429
It is: 499 -99.8 = 399.2