12X - 7 = 4X + 9 subtract 4X from both sides 8X - 7 = 9 add 7 to both sides 8X = 16 divide both sides by 8 X = 2 check 12(2) - 7 = 4(2) + 9 24 - 7 = 8 + 9 17 = 17 checks
4x-8x = -4x √-4x stands. However, x could not possibly be a positive number, because: (Negative) X (Positive) = (Negative) The square root of a negative number is undefined-so... (√-4x) + 9 Is your answer.
8x-3=6 8x=9 x=9/8=1 1/8=1.125
Given: f(x) = 2x2 - 8x + 9 This function describes a parabola, which only has one extreme value. To find that value, you can take the derivative of the function, and use that to find the point at which it has a slope of zero: f'(x) = 4x - 8 if f'(x) = 0, then: 0 = 4x - 8 ∴4x = 8 ∴ x = 2 Now we work out the corresponding value for f(2): f(2) = 2(2)2 - 8(2) + 9 = 8 - 16 + 9 = 1 So the extreme value for this function is 1, which occurs at the point (2, 1)
The answer is nine. Seriously. Here is my work if you don't believe me: 68=8x+23+4x-7x 68=8x-7x+23+4x 68=x+23+4x 68=x+4x+23 68=5x+23 68-23=5x 45=5x x=45/5 x=9
If: -9-4x = 7-8x Then: x = 4
12X - 7 = 4X + 9 subtract 4X from both sides 8X - 7 = 9 add 7 to both sides 8X = 16 divide both sides by 8 X = 2 check 12(2) - 7 = 4(2) + 9 24 - 7 = 8 + 9 17 = 17 checks
4x-8x = -4x √-4x stands. However, x could not possibly be a positive number, because: (Negative) X (Positive) = (Negative) The square root of a negative number is undefined-so... (√-4x) + 9 Is your answer.
8x - 4x + 7 = 94x + 7 = 94x = 9-74x = 2x = 4/2x = 1/2x = 0.5
8x^3 - 12x^2 + 6x - 9 = (8x^3 - 12x^2) + (6x - 9) = 4x^2(2x - 3) + 3(2x - 3) = (4x^2 + 3)(2x - 3)
Subtract 4x from each side: 4x + 9 = 25Subtract 9 from each side: 4x = 16Divide each side by 4: x = 4
8x-3=6 8x=9 x=9/8=1 1/8=1.125
Probably a quadratic equation problem.4X2 - 4X + 1 = 94X2 - 4X - 8 = 0factor out a 4 looks like a dead end, so....X = - b (+/-) sqrt(b2 - 4ac)/2aa = 4b = - 4c = - 8X = - (- 4) (+/-) sqrt[(- 4)2 -4(4)(- 8)]/2(4)X = 4 (+/-) sqrt(16 + 128)/8X = 4 (+/-) sqrt(144)/8X = [4 (+/-) 12]/8================X = 2X = - 1
Given: f(x) = 2x2 - 8x + 9 This function describes a parabola, which only has one extreme value. To find that value, you can take the derivative of the function, and use that to find the point at which it has a slope of zero: f'(x) = 4x - 8 if f'(x) = 0, then: 0 = 4x - 8 ∴4x = 8 ∴ x = 2 Now we work out the corresponding value for f(2): f(2) = 2(2)2 - 8(2) + 9 = 8 - 16 + 9 = 1 So the extreme value for this function is 1, which occurs at the point (2, 1)
The answer is nine. Seriously. Here is my work if you don't believe me: 68=8x+23+4x-7x 68=8x-7x+23+4x 68=x+23+4x 68=x+4x+23 68=5x+23 68-23=5x 45=5x x=45/5 x=9
The discriminant is 88.
(4x - 3)(2x + 3)