2/x + 5
x/(x + 4) = 4/(x + 4) + 2 (x - 4)/(x + 4) = 2 x - 4 = 2x + 8 -x = 12 x = -12
x over 4= 2x+3 over 15
If x/2 +3 = 4 then x = 2
6, 2
2/x + 5
x/(x + 4) = 4/(x + 4) + 2 (x - 4)/(x + 4) = 2 x - 4 = 2x + 8 -x = 12 x = -12
If: x + 2/2 + x + 5/7 = 4 Then: x = 8/7
x^2/x +2=4/x +2 (x^2/x)-(4/x)=0 (x^2-4)/x=0 x^2-4=0 (x+2)(x-2)=0 x=±2
Answer: x = 8/7
x over 4= 2x+3 over 15
If x/2 +3 = 4 then x = 2
6, 2
(x^2-4) (x^2+6x+8) __________ x _________ which is (x^2+2x-8) (x^2+4x+4) (x+2)(x-2) (x^2+4x+2x+8) ___________ x _____________ which is (x^2+4x-2x-8) (x^2+2x+2x+4) (x+2)(x-2) x(x+4)+2(x+4) ___________ x ____________ which is x(x+4)-2(x+4) x(x+2)+2(x+2) (x+2)(x-2) (x+2)(x+4) ________ x _________ which is 1 as all the terms in the num & den cancel (x-2)(x+4) (x+2)(x+2)
x=12 because 12 over 6 is 2,and 2 plus 4 is 6.
x > 10
You can divide the integers in this case - 4 divided by 2 and 9 divided by 3. You would get 2 over x plus 3 over x. 4/2x + 9/3x = 2/x + 3/x = 5/x