Q: What is 4c plus 1-(5 2c)?

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4c+1-5+2c = 6c-4.

4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)

6c-4c =2c

4c^2-12c+9 is a trinomial because it is in the form of ax^2 + bx + c. In this case, the trinomial is a perfect square trinomial. 4c^2-12c+9 =(2c-3)(2c-3) =(2c-3)^2

12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c

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8c2-26c+15 8c2-6c-20c+15 2c(4c-3)+5(-4c+3) (2c-5)(4c-3)

4c+1-5+2c = 6c-4.

4c-7 = 2c+11 4c-2c = 11+7 2c = 18 c = 9

4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)

2c+4c-3c+5c = 6c +2c = 8c

6c-4c =2c

(5a - 4b) + (2c - 3b - 6c) + a =5a - 4b + 2c - 3b - 6c + a =(5a + a) + (-4b - 3b) + (2c - 6c) =[ 6a - 7b - 4c ].

4c^2-12c+9 is a trinomial because it is in the form of ax^2 + bx + c. In this case, the trinomial is a perfect square trinomial. 4c^2-12c+9 =(2c-3)(2c-3) =(2c-3)^2

tell me time table of ME 2C drawing, ME 3C and 4C tell me time table of ME 2C drawing, ME 3C and 4C

12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c

Well I got this: 2c+7=9+6-7c+2c 2c+7=15-9c 11c+7=15 (add 9c) 11c=8 ( Subtract 7) 11---11 ( Divide 11) C=0.72

That's going to depend on the values of 'a', 'b', 'c', and 'f'.