Well the c stands for a number. So it means four times what plus three equals eleven? Or you can subtract the three from the eleven then divide that number by four. That's how to solve the problem. Sorry, I won't give you the answer though because you have to figure it out yourself if it's for school or something like that.
4c+3=11
.....-3.. -3
...4c= 8
..../4 /4
________
....c= ?
4c+1-5+2c = 6c-4.
8c + 5 = 4c - 11Subtract 4c from each side:4c + 5 = -11Subtract 5 from each side:4c = -16Divide each side by 4:c = -4
c = 6 and d = 7
48c + 408
1 and 3/4
17-3= 4c+3c c=2
0+11 1+10 2+9 3+8 4+7 5+6
8c2-26c+15 8c2-6c-20c+15 2c(4c-3)+5(-4c+3) (2c-5)(4c-3)
4c+2 = 3c+9 4c-3c = 9-2 c = 7
4c+1-5+2c = 6c-4.
It cannot be simplified any further so it is: 3a + 24b + 4c
1st:-4c- 11- 4c=4c+12- 4c2nd:-8c- 11+ 11=21+ 113rd:-8c/-8+ 32/-8c=-4
When c = -3 then 4c + 5c - 2 = [4 x -3] + [5 x -3] - 2 = -12 +(-15) - 2 = -12 -15 -2 = -29
4c
8c + 5 = 4c - 11Subtract 4c from each side:4c + 5 = -11Subtract 5 from each side:4c = -16Divide each side by 4:c = -4
4c-7 = 2c+11 4c-2c = 11+7 2c = 18 c = 9
c = 6 and d = 7