(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
The multiplicative inverse of a number a is a number b such that axb=1 If we look at (3-4i)/(5+2i), we see that we can multiply that by its reciprocal and the product is one. So (5+2i)/(3-4i) is the multiplicative inverse of (3-4i)/(5+2i)
To find the quotient of the complex numbers ( (4 + 4i) ) and ( (5 + 4i) ), you divide the two: [ \frac{4 + 4i}{5 + 4i}. ] To simplify, multiply the numerator and denominator by the conjugate of the denominator: [ \frac{(4 + 4i)(5 - 4i)}{(5 + 4i)(5 - 4i)} = \frac{(20 - 16i + 20i - 16)}{(25 + 16)} = \frac{(4 + 4i)}{41}. ] This results in ( \frac{4}{41} + \frac{4}{41}i ).
4 divided buy 1 third simplified = 4
It is: (3-54)/6 = -17/2 simplified
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
The multiplicative inverse of a number a is a number b such that axb=1 If we look at (3-4i)/(5+2i), we see that we can multiply that by its reciprocal and the product is one. So (5+2i)/(3-4i) is the multiplicative inverse of (3-4i)/(5+2i)
Soixante-neuf = 69I Love 69
To find the quotient of the complex numbers ( (4 + 4i) ) and ( (5 + 4i) ), you divide the two: [ \frac{4 + 4i}{5 + 4i}. ] To simplify, multiply the numerator and denominator by the conjugate of the denominator: [ \frac{(4 + 4i)(5 - 4i)}{(5 + 4i)(5 - 4i)} = \frac{(20 - 16i + 20i - 16)}{(25 + 16)} = \frac{(4 + 4i)}{41}. ] This results in ( \frac{4}{41} + \frac{4}{41}i ).
1.25
4 divided buy 1 third simplified = 4
-6-4i.
-9
(x - 4i)(x + 4i) where i is the square root of -1
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
1
0.4103