c = 25 4x2 + 20x + 25 (2x + 5)(2x + 5)
4x2-20+25 = (2x-5)(2x-5) when factored with the help of the quadratic equation formula.
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
12x2 + 20x - 25 IS a polynomial that factors into (2x + 5)(6x - 5)
Divide all terms by 4:- x2+5x-6 = (x-1)(x+6) when factored
4x2+20x+25 (2x+5)^2
c = 25 4x2 + 20x + 25 (2x + 5)(2x + 5)
The discriminant is 0.
(2x - 5)(2x - 5)
(2x - 5)(2x - 5) or (2x - 5) squared
4x2-20+25 = (2x-5)(2x-5) when factored with the help of the quadratic equation formula.
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
(x - 2)(x + 4)(x - 6)
Assuming the missing signs are pluses, that factors to (2x + 5)(2x + 5)
12x2 + 20x - 25 IS a polynomial that factors into (2x + 5)(6x - 5)
16x2 + 40x + 25 = 16x2 + 20x + 20x + 25 = 4x(4x + 5) + 5(4x + 5) = (4x + 5)(4x + 5) = (4x + 5)2
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.