y = mx + b 4x - 3y = 3 -3y = -4x + 3 y = 4/3x - 1
4x = -3y+8 3y = -4x+8 y = -4/3x+8/3 So the slope is -4/3 or -1 and a 1/3
4x+3y = 3 3y = -4x+3 y = -4/3x+1 in slope intercept form
3y = 4x + 9 -4x + 3y = 9 is the standard form
-4x + 3y = 9
If: -4x+3y = 1 Then: 3y = 4x+1 And: y = 4/3x+1/3 which is now in slope-intercept form
y = mx + b 4x - 3y = 3 -3y = -4x + 3 y = 4/3x - 1
4x = -3y+8 3y = -4x+8 y = -4/3x+8/3 So the slope is -4/3 or -1 and a 1/3
x - 3y = 11 So x = 11 + 3y Then, by the other equation, 4x + 3y = -1 becaomes 4(11+3y) + 3y = -1 or 44 + 12y + 3y = -1 or 15y = -45 so that y = -3
4x+3y = 3 3y = -4x+3 y = -4/3x+1 in slope intercept form
3y = 4x + 9 -4x + 3y = 9 is the standard form
-4x + 3y = 9
There are two simultaneous equations, so to solve for y, eliminate x: 1) 2x + 3y = 3 2) 4x - 3y = 9 Multiply equation (1) by 2 giving: 1) 4x + 6y = 6 2) 4x - 3y = 9 Next, subtract equation (2) from equation (1), giving: (4x - 4x) + (6y - -3y) = 6 - 9 → 9y = -3 → y = -1/3
3y=4x+9.....-4xAnswer: 4x-3y=9
4x+3y = 12 3y = -4x+12 y = -4/3x+4
-1/2
4x + 3y=9 x=0 y=3