To add (5.8 \times 10^{-3}) and (1.6 \times 10^{-6}), we first convert (1.6 \times 10^{-6}) to the same exponent as the first term. This becomes (0.0000016), or in scientific notation, (0.0000016 = 0.0000058) when expressed with the same exponent. Therefore, (5.8 \times 10^{-3} + 0.0000016) is approximately (5.8000016 \times 10^{-3}), which can be written as (5.8 \times 10^{-3}) when rounded to three significant figures.
3.12 X10^-5 (^-5 = to the power of minus 5)
570,000,000
0.00604
x25 x10
3,480,000
3.12 X10^-5 (^-5 = to the power of minus 5)
3 x10 30 x10
0.000000001
2.058911321...x10^14
570,000,000
350000
29000000
2.3*107 = 23,000,000
0.00604
x25 x10
Yes, if x10=y.
Yes