500% = 500/100 = 5.0 Answer #2 I disagree with the first answer. 1x is 100% 5x is 500% 50x is 5000% and 500x is 50000%
The graph that you use is parabolic. Use the quadratic function y=ax^2 + bx + c and three points to find the equasion you would need to use. Points are as follows, (day(x), money(y)) (0,0) day zero start wth nothing (1,1000) day 1, 1000 (2,3000) day 2, 2000 plus previous days y = a(x)^2 + b(x) + c using first point: 0 = a(0)^2 + b(0) + c 0 = c using second point, and c from above: 1000 = a(1)^2 + b(1) + (0) 1000 = a + b 1000 - a = b using third point and b and c from above: 3000 = a(2)^2 + (1000 - a)(2) + (0) 3000/2 = (4a + 2(1000 - a))/2 1500 = 2a + 1000 - a 1500 = a + 1000 500 = a since we now have an exact a and exact c we can find exact b from second statement: 1000 - a = b 1000 - (500) = b 500 = b therefore to find the equasion, plug the slopes back into the formula y=ax^2 + bx + c. y = 500x^2 + 500x y being the amount of money and x being the amount of days, solve for x, when looking for $1,000,000: 1000000 = 500x^2 + 500x x is approx 44.224154548 days since you are getting whole thousands each day, we cannot use partial days. so round down and up and plug in x and solve for y: y = 500x^2 + 500x y = 500(44)^2 + 500(44) y = 990000 y = 500x^2 + 500x y = 500(45)^2 + 500(45) y = 1035000 in conclusion, it would take 45 days to have 1 million dollars.
45............... 500x.09=45. simple matr
x - 0.5% = 500x - .005 = 500x - .005 + .005 = 500 + .005x = 500.005Check:x = 500.005500.005 - 0.5% = 500500.005 - .005 = 500500 = 500So x - 0.5% = 500 when x is .005.
50,0001/100=500/xx=100*500x=50,000
The total magnification of the microscope would be 10X (ocular lens) multiplied by 50X (objective lens) which equals 500X.
1000/500 = 2x500=1000x500=1000_________500 500x=2
500x * 40 = 20000x
500x.20=100.
This problem can be solved by the following equation:500x=1000 500x/500=1000/500 x=2mph
500% = 500/100 = 5.0 Answer #2 I disagree with the first answer. 1x is 100% 5x is 500% 50x is 5000% and 500x is 50000%
The graph that you use is parabolic. Use the quadratic function y=ax^2 + bx + c and three points to find the equasion you would need to use. Points are as follows, (day(x), money(y)) (0,0) day zero start wth nothing (1,1000) day 1, 1000 (2,3000) day 2, 2000 plus previous days y = a(x)^2 + b(x) + c using first point: 0 = a(0)^2 + b(0) + c 0 = c using second point, and c from above: 1000 = a(1)^2 + b(1) + (0) 1000 = a + b 1000 - a = b using third point and b and c from above: 3000 = a(2)^2 + (1000 - a)(2) + (0) 3000/2 = (4a + 2(1000 - a))/2 1500 = 2a + 1000 - a 1500 = a + 1000 500 = a since we now have an exact a and exact c we can find exact b from second statement: 1000 - a = b 1000 - (500) = b 500 = b therefore to find the equasion, plug the slopes back into the formula y=ax^2 + bx + c. y = 500x^2 + 500x y being the amount of money and x being the amount of days, solve for x, when looking for $1,000,000: 1000000 = 500x^2 + 500x x is approx 44.224154548 days since you are getting whole thousands each day, we cannot use partial days. so round down and up and plug in x and solve for y: y = 500x^2 + 500x y = 500(44)^2 + 500(44) y = 990000 y = 500x^2 + 500x y = 500(45)^2 + 500(45) y = 1035000 in conclusion, it would take 45 days to have 1 million dollars.
45............... 500x.09=45. simple matr
x - 0.5% = 500x - .005 = 500x - .005 + .005 = 500 + .005x = 500.005Check:x = 500.005500.005 - 0.5% = 500500.005 - .005 = 500500 = 500So x - 0.5% = 500 when x is .005.
500x.1=50Quick check-50x10=500It is 50
The answer is 1000000 so this is 1 million if I counted correctly.
A regular microscope, use the 500X for details.