-52 - 3 + 63 -52 + 66 + 14
52
To be rational, the numerator has to be a factor of 52 (the last term), and the denominator has to be a factor of 3 (the coefficient of the first term). Try all the combinations, including negative numbers (52/1, -52/1, 52/3, -52/3, 26/1, 26/3, etc.), to see whether one of them is a zero.
3 pluses
Six
3+52+4 52+3=55+4 55+4=59
-52 - 3 + 63 -52 + 66 + 14
52
52 = 4 + (n - 1)³ → (n - 1)³ = 48 → n - 1 = ³√48 → n = 1 + ³√48 ≈ 4.634
49 + 3 = 52
To be rational, the numerator has to be a factor of 52 (the last term), and the denominator has to be a factor of 3 (the coefficient of the first term). Try all the combinations, including negative numbers (52/1, -52/1, 52/3, -52/3, 26/1, 26/3, etc.), to see whether one of them is a zero.
No. 52 out of 90 is equal to 171/3 out of 30 . 52 out of 60 is equal to 26 out of 30 .
x + 52 + 2y + 35 = 3 x + 2y = 3 - 52 -35 x + 2y = -84 Infinite number of solutions, are you sure you posted the correct equation?
3 pluses
-1
-3
3 + 3 + 3 + 6 + 9 = 24