56
14 + 14 + 14 + 14 = 56 There are four equal groups of 14 in 56 4 x 14 = 56 56 divided by 4 = 14
n2 = 10n + 56 Subtract (10n + 56) from each side: n2 - 10n - 56 = 0 Now you have something on the left side that you can factor: (n - 14) (n + 4) = 0 n = +14 n = - 4
56 - 14 = 42
14 * 56 = 784
56
In this problem, if I understand correctly, you are solving for the variable, nn + 14 = 56-14 -1414 will cancel out giving youn = 42
324
14 + 14 + 14 + 14 = 56 There are four equal groups of 14 in 56 4 x 14 = 56 56 divided by 4 = 14
14
It is: 14/56 = 1/4 by dividing 14 and 56 by their HCF which is 14
56. (8 * 7 = 56) (14 * 4 = 56)
n2 = 10n + 56 Subtract (10n + 56) from each side: n2 - 10n - 56 = 0 Now you have something on the left side that you can factor: (n - 14) (n + 4) = 0 n = +14 n = - 4
56 x 0.25 = 14, so:14 is 25% of 56.
56 - 14 = 42
14 * 56 = 784
-112