114
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Any of its multiples! Simply calculate any of the following: 57 x 0 57 x 1 57 x 2 57 x 3 57 x (-1) 57 x (-2) etc., and you get a number that is a multiple of 57, and therefore, divisible by 57.
The six multiples are: 57 x 1 = 57 57 x 2 = 114 57 x 3 = 171 57 x 4 = 228 57 x 5 = 285 57 x 6 = 342
60
1 x 114, 2 x 57, 3 x 38, 6 x 19, 19 x 6, 38 x 3, 57 x 2, 114 x 1
Algebraically.X + ( X + 2) = - 1162X + 2 = - 1162X = - 118X = - 59X + 2 = - 57- 59 (+) - 57 = - 116( - 57, - 59 )------------------solution set